Table of Contents

- 1 How many bits does it take to store a number?
- 2 How many bits are needed to store 256?
- 3 How many bits do you need to represent 500 in binary?
- 4 How many bits are required to represent 1000 things?
- 5 How many bits is 4 bytes?
- 6 Why is 4 bits called a nibble?
- 7 How many bits do you need to store 3 values?
- 8 How to calculate the number of binary bits required to store an integer?

## How many bits does it take to store a number?

1 Integers. Integers are commonly stored using a word of memory, which is 4 bytes or 32 bits, so integers from 0 up to 4,294,967,295 (232 – 1) can be stored. Below are the integers 1 to 5 stored as four-byte values (each row represents one integer).

### How many bits are needed to store 256?

8 bits

You need more than 8 bits to store more than 256 values, yes, because 2^8 is 256.

**How many bits does it take to store 8000000?**

Orders of magnitude (data)

Binary [bits] | Item |
---|---|

Factor | |

8,000,000 bits (1,000 kilobytes) – the preferred definition of megabyte | |

8,343,400 bits – one “typical” sized photograph with reasonably good quality (1024 × 768 pixels). | |

223 | 8,388,608 bits (1,024 kibibytes), one of a few traditional meanings of megabyte |

**What is 16 bits called?**

Common binary number lengths Each 1 or 0 in a binary number is called a bit. From there, a group of 4 bits is called a nibble, and 8-bits makes a byte. It could be 16-bits, 32, 64, or even more.

## How many bits do you need to represent 500 in binary?

9 bits

500 in binary is 111110100. Unlike the decimal number system where we use the digits 0 to 9 to represent a number, in a binary system, we use only 2 digits that are 0 and 1 (bits). We have used 9 bits to represent 500 in binary.

### How many bits are required to represent 1000 things?

Using the above formula you’ll see that the smallest four-digit number, 1000, requires 10 bits, and the largest four-digit number, 9999, requires 14 bits. The number of bits varies between those extremes. For example, 1344 requires 11 bits, 2527 requires 12 bits, and 5019 requires 13 bits. Why does this occur?

**Is 4 bits enough to store 8 directions?**

Each direction is stored in memory as a sequence of four bits. Four bits are not enough to store the eight directions.

**Why do bytes have 8 bits?**

The byte was originally the smallest number of bits that could hold a single character (I assume standard ASCII). We still use ASCII standard, so 8 bits per character is still relevant. This sentence, for instance, is 41 bytes. That’s easily countable and practical for our purposes.

## How many bits is 4 bytes?

32 bits

We say that 8 bits is a byte. Whole numbers (integers) are usually represented with 4 bytes, or 32 bits.

### Why is 4 bits called a nibble?

The term nibble originates from its representing “half a byte”, with byte a homophone of the English word bite. An 8-bit byte is split in half and each nibble is used to store one decimal digit.

**Why is 16 bits called a word?**

For example, the MS Windows WORD datatype was defined back in the early days, when 16-bit CPUs were the norm. When 32-bit CPUs came around, the definition stayed, and a 32-bit integer became a DWORD .

**How is binary calculated?**

Converting decimal integer to binary To convert integer to binary, start with the integer in question and divide it by 2 keeping notice of the quotient and the remainder. Continue dividing the quotient by 2 until you get a quotient of zero. Then just write out the remainders in the reverse order.

## How many bits do you need to store 3 values?

So to store 3 values, you need at least two bits. You need more than 8 bits to store more than 256 values, yes, because 2^8 is 256. TL;DR: two digits. In any number base system, the number of values that can be held by a single digit is equal to the base number, so for the regular base-10 number system, that would be 10 (0 through 9).

### How to calculate the number of binary bits required to store an integer?

The formula for the number of binary bits required to store n integers (for example, 0 to n – 1) is: log e(n) / log e(2) and round up. For example, for values -128 to 127 (signed byte) or 0 to 255 (unsigned byte), the number of integers is 256, so n is 256, giving 8 from the above formula.

**How many bits does a 1000 digit number need?**

Where n is the numbers of bits and R is the number of symbols for the representation. For the decimal number system R=9 so we solve 9=2^n, the answer is 3.17 bits per decimal digit. Thus a 3 digit number will need 9.51 bits or 10. A 1000 digit number needs 3170 bits

**How many base 2 digits do you need?**

Two base-2 digits (or binary digits, or bits) can hold values 00 through 11, so 4; with three bits 00 through 111, so 8; with four bits 00 through 1111, so 16; with eight (a byte) 00000000 through 11111111, so 256. So, in order to hold three values – e.g., 0 1 and 2 base-10 – you’d need two digits: 00 01 and 10 binary.