What would be the final temperature of mixture of 40 grams of water at 20 degrees Celsius mixed with 60 grams of water at 30 degrees Celsius?

What would be the final temperature of mixture of 40 grams of water at 20 degrees Celsius mixed with 60 grams of water at 30 degrees Celsius?

Answer: since it is given that 40 gms water at 20 ⁰ C and 40 gms of water at 40⁰ C are mixed. Since the masses of the liquid at different temperatures are same, the answer is very easy and simple : average of 20⁰C and 40⁰C. that is: 30⁰C.

How do you find the final temperature of mixed water?

Calculate the final temperature of the water mixture using the equation T(final) = (m1_T1 + m2_T2) / (m1 + m2), where m1 and m2 are the weights of the water in the first and second containers, T1 is the temperature of the water in the first container and T2 is the temperature of the water in the second container.

What would be the final temperature of a mixture of 50 g of water at 20 C temperature and 50 g of water at 40 C temperature?

Let the final temperature of the mixture of 50g of water at 20°C temperature and 50g of water at 40°C be T. Let the specific heat capacity of water be S. Hence, the final temperature of a mixture of 50g of water at 20°C temperature and 50g of water at 40°C temperature would be 30°C.

How do you calculate heat gained by water?

Calculate the heat gained by the water using Equation 1 from the Background section. The mass of water used is 50.0 g and the specific heat of water (C) is 1.0 cal/g °C. These values will give you the heat gained in calories. Q = m × C × ∆T = 50.0 g × 1.0 cal/g°C × 5.3 °C = 265 cal.

What is the final temperature?

Add the change in temperature to your substance’s original temperature to find its final heat. For example, if your water was initially at 24 degrees Celsius, its final temperature would be: 24 + 6, or 30 degrees Celsius.

When 50 grams of water at 20 degrees Celsius is mixed with 50 grams of water at 100 degree Celsius what is the result?

Explanation: since it is given that 50 gms water at 20 ⁰ C and 50 gms of water at 40⁰ C are mixed. Since the masses of the liquid at different temperatures are same, the answer is very easy and simple : average of 20⁰C and 40⁰C. that is: 30⁰C.

How do you solve for the final temperature?

What is the final temperature of the mixture of 50g of steam?

Answer: The final temperature will be 0°C.

What is the formula for heat gained?

The heat gained by the calorimeter, q cal, is determined from the formula, qcal = Ccal×Δt, where Δt is the change in temperature undergone by the mixture. NOTE: To use the Ccal the exact same mass(100.0 g) must be used as in part I.

How do you find the final temperature of the heat capacity?